# Misc 8 - Chapter 9 Class 12 Differential Equations (Term 2)

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Misc 8 Find the equation of the curve passing through the point 0 , 4 whose differential equation is sin cos + cos sin =0 sin x cos y dx + cos x sin y dy = 0 sin x cos y dx = cos x sin y dy sin cos = sin cos Integrating both sides sin cos = sin cos sin sin = sin sin = log = + log + log = c log . = Put values of u and v. log cos . cos = c Since the curve passes through 0, 4 Putting x = 0 and y = 4 in (1) log cos 0 .cos 4 = log 1. 1 2 = C = log 1 2 Substitute value of C in (2) log cos cos = log cos . cos = log 1 2 cos x. cos y = 1 2 cos y = 1 2 cos cos y =

Miscellaneous

Misc 1 (i)

Misc 1 (ii)

Misc 1 (iii) Important

Misc 2 (i)

Misc 2 (ii) Important

Misc 2 (iii)

Misc 2 (iv) Important

Misc 3 Deleted for CBSE Board 2022 Exams

Misc 4 Important

Misc 5 Important Deleted for CBSE Board 2022 Exams

Misc 6

Misc 7 Important

Misc 8 You are here

Misc 9 Important

Misc 10 Important

Misc 11

Misc 12 Important

Misc 13

Misc 14 Important

Misc 15 Important

Misc 16 (MCQ)

Misc 17 (MCQ) Important Deleted for CBSE Board 2022 Exams

Misc 18 (MCQ)

Chapter 9 Class 12 Differential Equations (Term 2)

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.